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we have proposed a more efficient vs the average cost of encoding

These two phrases are not directly comparable as they convey different ideas. The first phrase talks about proposing something more efficient, while the second phrase mentions the average cost of encoding. They serve different purposes and cannot be interchanged.

Last updated: March 08, 2024 • 512 views

we have proposed a more efficient

This phrase is correct and commonly used in English.

This phrase is used to indicate that a proposal for something more efficient has been put forward.
  • In our recent work, we have proposed a more efficient alternative to March RAW [ 7]. Without increasing its complexity, we have improved the standard March C-.
  • sensitize the fault, the test complexity increases dramatically. In [Dili04c] we have proposed a more efficient alternative to March RAW. For this purpose, we have.
  • May 8, 2014 ... In recent work (Sengupta et al., in press) we have proposed a more efficient “ adjoint method,” which computes gradients and curvatures as part ...
  • May 8, 2014 ... In recent work (Sengupta et al., in press) we have proposed a more efficient “ adjoint method,” which computes gradients and curvatures as part ...

the average cost of encoding

This phrase is correct and commonly used in English.

This phrase is used to refer to the typical cost associated with encoding data or information.
  • We also establish the same bound on the average cost of encoding the edges of G as dis·. tinCt paths in H . Categories and Subject Descriptors: F.2.2 [Analysis ...
  • Feb 22, 2012 ... The mean rate of vesicle release through linear ON terminals was 15.5 vesicles s −1, so the average cost of encoding luminance was 2.51 ...
  • ... entropies, including the Shannon entropy) is discussed, and a new lower bound for the average cost of encoding the messages to be transmitted is obtained.
  • Let us assume that the average cost of encoding one such additional regulation is ln. Hence, the total cost of additional deficit regulations is NDEF = ln ndef.

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