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to recover the original string from vs the algorithm first scans

These two phrases are not directly comparable as they serve different purposes. The first phrase 'to recover the original string from' is used to describe a process of retrieving information, while the second phrase 'the algorithm first scans' introduces a step in a process. They can be used in different contexts and are not interchangeable.

Last updated: March 15, 2024 • 442 views

to recover the original string from

This phrase is correct and commonly used in English.

This phrase is used to describe the action of retrieving the original string from a certain source or format.
  • For a human it is generally very easy to recover the original string from. the distorted image, but it is difficult for state of the art character recognition. algorithms to ...
  • ... and the combine the generated key with the encrypted string using bit-wise Exclusive OR to recover the original string from cipher string and break the code.
  • Aug 26, 1983 ... time to recover the original string from this encoding. Hence, we shall use non- determinism to be able to simulate knowing a string's position in ...
  • Jan 3, 2014 ... It is well-known that the. LF -mapping can not only be used to recover the original string from the BWT but also its suffix array. This is a direct.

the algorithm first scans

This phrase is correct and commonly used in English.

This phrase is used to introduce the initial step in a process where an algorithm scans or examines data.
  • Mar 3, 2015 ... For example, the algorithm first scans through the input performing 1-by-1 merges to produce ordered sub-arrays of size 2; then, it scans ...
  • The main procedure. The main procedure of TopSeqRules is shown in figure 2. The algorithm first scans the database once to calculate sids(c) for each item c.
  • The algorithm first scans the database to calculate the TWU of each item. Then, the algorithm identifies the set I∗ of all items having a. TWU no less than minutil ...
  • The algorithm first scans both inputs and offloads k partitions. Assuming inputs T and V with. |T|≤|V| and also assuming that our memory budget M is greater.

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